bind a xml result into datagrid in silverlight

first check : AutoGenerateColumns="True" in datagrid.

if you want to do in web services or asp.net places:

XmlDocument xml = new XmlDocument();
         xml.LoadXml(response);
         XmlNodeList xnList = xml.SelectNodes("/person");

         //int[] ids = new int[10];
       
         //string[] str = new string[10];
         //int i = 0;
         string firstName="", lastName="", headline="";
         foreach (XmlNode xn in xnList)
         {
              firstName = xn["first-name"].InnerText;
              lastName = xn["last-name"].InnerText;
              headline = xn["headline"].InnerText;
             //string url = xn["url"].InnerText;
             //Console.WriteLine("Name: {0} {1}", firstName, lastName);
         }

XmlDocument will work.

if you want to do in silverlight scree:
first check the result which fields are coming in result.

if you are getting result like:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<person>
  <first-name>Damu</first-name>
  <last-name>P</last-name>
  <headline>--</headline>
  <site-standard-profile-request>
    <url>http://www.linkedin.com/profile?viewProfile=&amp;key=123089296&amp;authToken=NpQD&amp;authType=name&amp;trk=api*a170167*s178416*</url>
  </site-standard-profile-request>
</person>

then we need to print this xml in datagrid:

for this first create on class function in silverlight screen:

   public class Person
        {
          
            public string firstname { get; set; }
            public string lastname { get; set; }
            public string headline { get; set; }
            public string url { get; set; }
            //public Uri sitestandardprofilerequest { get; set; }        
       
    }

then :

XDocument xdoc = XDocument.Parse(e.Result);
            List<Person> _PersonList = new List<Person>(10);
            Person obj = new Person();
            string[] a = new string[] { };
            int i=0;
            var persons = from d in xdoc.Elements("person")
                        select d;
          
            foreach (var _persons in persons)
            {
              
                obj.firstname=_persons.Element("first-name").Value.ToString();
                obj.lastname = _persons.Element("last-name").Value.ToString();
                obj.headline = _persons.Element("headline").Value.ToString();
                obj.url = _persons.Element("site-standard-profile-request").Element("url").Value.ToString();
                _PersonList.Add(obj);
                i++;
              
              
            }

            dataGrid1.ItemsSource = _PersonList;

you will get the result in grid view.